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Matches 1 to 3 of 3 for Last Name equals BRINKMANS AND Tree equals Sonneveld 2

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 #  Last Name, Given Name(s)    Person ID   Born/Christened    Location 
1
Brinkmans, Jan
I39920  b. 8 Dec 1890 Ambt Almelo, Overijssel, Netherlands  
2
Brinkmans, Jan Hendrik
I39921  b. 31 Dec 1862 Markelo, Overijssel, Netherlands  
3
Brinkmans, Jenneken
I27067    

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